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	<title>Comments on: The Dice Brain Teaser: A Technical Interview Question that Can Help You Solve Problems Better</title>
	<atom:link href="http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/feed/" rel="self" type="application/rss+xml" />
	<link>http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/</link>
	<description>Articles on game theory and personal finance</description>
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		<title>By: Faisal</title>
		<link>http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/comment-page-1/#comment-13128</link>
		<dc:creator>Faisal</dc:creator>
		<pubDate>Fri, 16 Dec 2011 23:27:06 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/#comment-13128</guid>
		<description>Here is how I solved the problem:

Probability I win in any given round - 1/6

Probability that my opponent wins in any given round - (5/6)*(1/6) = 5/36

Since we keep playing till we have a winner, we just need to normalize the above two probabilities.

So the probability I win the game is - 
(1/6)/[(1/6)+(5/36)] = (6/36)/(11/36) = 6/11

So I do get the same answer, with slightly different logic.</description>
		<content:encoded><![CDATA[<p>Here is how I solved the problem:</p>
<p>Probability I win in any given round &#8211; 1/6</p>
<p>Probability that my opponent wins in any given round &#8211; (5/6)*(1/6) = 5/36</p>
<p>Since we keep playing till we have a winner, we just need to normalize the above two probabilities.</p>
<p>So the probability I win the game is &#8211;<br />
(1/6)/[(1/6)+(5/36)] = (6/36)/(11/36) = 6/11</p>
<p>So I do get the same answer, with slightly different logic.</p>
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		<title>By: A Day in the Life of a Game Theorist: A Tribute to One Year of Game Theory Tuesdays - Mind Your Decisions</title>
		<link>http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/comment-page-1/#comment-9521</link>
		<dc:creator>A Day in the Life of a Game Theorist: A Tribute to One Year of Game Theory Tuesdays - Mind Your Decisions</dc:creator>
		<pubDate>Sat, 20 Aug 2011 06:14:08 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/#comment-9521</guid>
		<description>[...] Darn you, Presh. You make infinite series seem so conventional. Aside from that, I absolutely adore the third solution. Erik in The Dice Brain Teaser (link) [...]</description>
		<content:encoded><![CDATA[<p>[...] Darn you, Presh. You make infinite series seem so conventional. Aside from that, I absolutely adore the third solution. Erik in The Dice Brain Teaser (link) [...]</p>
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		<title>By: Puzzle: how often does it rain? - Mind Your Decisions</title>
		<link>http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/comment-page-1/#comment-8587</link>
		<dc:creator>Puzzle: how often does it rain? - Mind Your Decisions</dc:creator>
		<pubDate>Mon, 20 Jun 2011 21:06:37 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/#comment-8587</guid>
		<description>[...] Hint 1 You can solve this by using the law of total probability (as an example, this is used in solution method 3 of the dice brain teaser) [...]</description>
		<content:encoded><![CDATA[<p>[...] Hint 1 You can solve this by using the law of total probability (as an example, this is used in solution method 3 of the dice brain teaser) [...]</p>
]]></content:encoded>
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		<title>By: Quick puzzle: how long to get to heaven? - Mind Your Decisions</title>
		<link>http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/comment-page-1/#comment-8581</link>
		<dc:creator>Quick puzzle: how long to get to heaven? - Mind Your Decisions</dc:creator>
		<pubDate>Mon, 20 Jun 2011 20:19:26 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/#comment-8581</guid>
		<description>[...] Hint: see method 3 of the dice brain teaser [...]</description>
		<content:encoded><![CDATA[<p>[...] Hint: see method 3 of the dice brain teaser [...]</p>
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		<title>By: Janus</title>
		<link>http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/comment-page-1/#comment-8112</link>
		<dc:creator>Janus</dc:creator>
		<pubDate>Sun, 06 Feb 2011 20:18:30 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/2008/05/20/the-dice-brain-teaser-a-technical-interview-question-that-can-help-you-solve-problems-better/#comment-8112</guid>
		<description>@Rob:

Here is the first line in the description of the problem: &quot;You and I play a game where we take turns rolling a die. I win if I roll a 4. You win if you roll a 5.&quot; Note, it stipulates that the players take turns. Plural &quot;turns.&quot; Not each take one turn. The clarifying notes make clear that this game continues until one wins. Since player 1 winning and player 2 winning are mutually exclusive events, you are essentially making the claim that the probability of player 2 winning is 5/6, since the probability of player 1 winning is 1/6.

I&#039;m not sure why you think that when we all answer 6/11 we are referring to odds.

And if you still think that the probability of player 1 winning is 1/6, I will happily play this game (as player 1) over and over with you according to the rules set out in the post. I can almost guarantee that I will come out way ahead of you.</description>
		<content:encoded><![CDATA[<p>@Rob:</p>
<p>Here is the first line in the description of the problem: &#8220;You and I play a game where we take turns rolling a die. I win if I roll a 4. You win if you roll a 5.&#8221; Note, it stipulates that the players take turns. Plural &#8220;turns.&#8221; Not each take one turn. The clarifying notes make clear that this game continues until one wins. Since player 1 winning and player 2 winning are mutually exclusive events, you are essentially making the claim that the probability of player 2 winning is 5/6, since the probability of player 1 winning is 1/6.</p>
<p>I&#8217;m not sure why you think that when we all answer 6/11 we are referring to odds.</p>
<p>And if you still think that the probability of player 1 winning is 1/6, I will happily play this game (as player 1) over and over with you according to the rules set out in the post. I can almost guarantee that I will come out way ahead of you.</p>
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