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	<title>Comments on: Game theory and the math of infinity</title>
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	<link>http://mindyourdecisions.com/blog/2008/11/04/game-theory-and-the-math-of-infinity/</link>
	<description>Articles on game theory and personal finance</description>
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		<title>By: Alexander</title>
		<link>http://mindyourdecisions.com/blog/2008/11/04/game-theory-and-the-math-of-infinity/comment-page-1/#comment-12640</link>
		<dc:creator>Alexander</dc:creator>
		<pubDate>Wed, 23 Nov 2011 05:48:20 +0000</pubDate>
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		<description>If you limit it to integers and have a initial group of 1 to 10, alice can use the same logic.
Also if Alice chooses 0.001-0.999 and initially chooses 0.002 then all she needs to do is make sure x is less than 0.999 If Bob picks ANY number in sub set S (S1, S3, S9001...) Alice can&#039;t lose even if she tries to. So Bob&#039;s strategy doesn&#039;t work, no matter if it&#039;s part of a set with countable infinite number or not, the original set could be all numbers = to 1+1/n where n is a positive interger.</description>
		<content:encoded><![CDATA[<p>If you limit it to integers and have a initial group of 1 to 10, alice can use the same logic.<br />
Also if Alice chooses 0.001-0.999 and initially chooses 0.002 then all she needs to do is make sure x is less than 0.999 If Bob picks ANY number in sub set S (S1, S3, S9001&#8230;) Alice can&#8217;t lose even if she tries to. So Bob&#8217;s strategy doesn&#8217;t work, no matter if it&#8217;s part of a set with countable infinite number or not, the original set could be all numbers = to 1+1/n where n is a positive interger.</p>
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		<title>By: Sauron</title>
		<link>http://mindyourdecisions.com/blog/2008/11/04/game-theory-and-the-math-of-infinity/comment-page-1/#comment-12087</link>
		<dc:creator>Sauron</dc:creator>
		<pubDate>Wed, 19 Oct 2011 01:16:36 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/?p=807#comment-12087</guid>
		<description>This seems to be just a game created out of Cantor&#039;s first uncountability proof.  While useful for explaining the concept to game theorists, it&#039;s not particularly novel.</description>
		<content:encoded><![CDATA[<p>This seems to be just a game created out of Cantor&#8217;s first uncountability proof.  While useful for explaining the concept to game theorists, it&#8217;s not particularly novel.</p>
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		<title>By: A math game of dodgeball - Mind Your Decisions</title>
		<link>http://mindyourdecisions.com/blog/2008/11/04/game-theory-and-the-math-of-infinity/comment-page-1/#comment-12077</link>
		<dc:creator>A math game of dodgeball - Mind Your Decisions</dc:creator>
		<pubDate>Tue, 18 Oct 2011 05:02:47 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/?p=807#comment-12077</guid>
		<description>[...] As you can see, game theory can make set theory a bit more interesting. If you like this post, you will also like a previous one I wrote about a game that proves the real numbers are uncountably large. [...]</description>
		<content:encoded><![CDATA[<p>[...] As you can see, game theory can make set theory a bit more interesting. If you like this post, you will also like a previous one I wrote about a game that proves the real numbers are uncountably large. [...]</p>
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		<title>By: Presh Talwalkar</title>
		<link>http://mindyourdecisions.com/blog/2008/11/04/game-theory-and-the-math-of-infinity/comment-page-1/#comment-6094</link>
		<dc:creator>Presh Talwalkar</dc:creator>
		<pubDate>Wed, 23 Dec 2009 19:04:43 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/?p=807#comment-6094</guid>
		<description>&lt;b&gt;&lt;em&gt;Chris&lt;/b&gt;&lt;/em&gt;: You&#039;re right! Bob can definitely throw the game, just as one could lose in tic-tac-toe or in &lt;a href=&quot;http://en.wikipedia.org/wiki/Hex_(board_game)&quot; rel=&quot;nofollow&quot;&gt;Hex&lt;/a&gt; (a game with an unknown but provably winnable strategy for the first player).

So whether Bob does win a particular game is irrelevant to the proof. And in fact, this game is not really practical to play--who has potentially infinite time to play a game?</description>
		<content:encoded><![CDATA[<p><b><em>Chris</em></b>: You&#8217;re right! Bob can definitely throw the game, just as one could lose in tic-tac-toe or in <a href="http://en.wikipedia.org/wiki/Hex_(board_game)" rel="nofollow">Hex</a> (a game with an unknown but provably winnable strategy for the first player).</p>
<p>So whether Bob does win a particular game is irrelevant to the proof. And in fact, this game is not really practical to play&#8211;who has potentially infinite time to play a game?</p>
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		<title>By: Chris</title>
		<link>http://mindyourdecisions.com/blog/2008/11/04/game-theory-and-the-math-of-infinity/comment-page-1/#comment-6088</link>
		<dc:creator>Chris</dc:creator>
		<pubDate>Tue, 22 Dec 2009 20:24:56 +0000</pubDate>
		<guid isPermaLink="false">http://mindyourdecisions.com/blog/?p=807#comment-6088</guid>
		<description>Just because Bob CAN win, doesn&#039;t mean he WILL necessarily win. How would Bob know which subset Alice picked before the game started?</description>
		<content:encoded><![CDATA[<p>Just because Bob CAN win, doesn&#8217;t mean he WILL necessarily win. How would Bob know which subset Alice picked before the game started?</p>
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